2x2 Cll Algorithms Pdf Merge

Introduction This solution method is designed to solve Rubik's cube and to solve it quickly, efficiently, and without having to memorize a lot of sequences. For ease and speed of execution, turns are mostly restricted to the top, right, and front faces, and center and middle slices.

X1 = 5 − 2x2 − x3. Substituting this into the objective and the second constraint, we obtain the equiva- lent problem (subtracting five from the objective). It is possible to combine the two phases of the two-phase method into a single. See, e.g., Cook [C5], Hartmanis and Stearns [H5] and Papadimitriou and Steiglitz.

Strong preference is given to the right face, since it is one of the easiest faces to turn for many people. Yet all sequences are minimal (or very close to minimal) by the slice-turn metric. For an introduction to the notation used in this page, go to the. This solution method orients cubies before positioning them. The idea is that it is easier to permute cubies after they've been oriented than before orienting them, because once the cubies have been oriented, the facelet colors that determine their permutation make easily identifiable patterns on the cube.

Orienting cubies, whether done before or after positioning them, is always easy because orientation requires focusing on only one face color and on the patterns that that color makes on the cube. For middle-slice edges on the last layer, permuting cubies after they've been oriented is a very simple affair, thus reinforcing this principle.

Do not worry about centers or edges while solving corners. Position centers while beginning to solve edges. You really only need to position top and bottom centers at that point, but positioning all centers may make things easier for you. Middle-slice centers will be positioned along with middle-slice edges on the last step. This solution method is based on Minh Thai's Winning Solution. Drum Sounds Wav Download Music. Ideas and sequences are borrowed from other solution methods, and appropriate attributions are made in those sections. Solving Corners Orient Top Corners.

A pair here represents two adjacent corners on the top or bottom layer. Such a pair is considered to be solved correctly if the two corners are positioned correctly relative to each other. A solved pair will be easy to identify because the two adjacent facelets on the side (not top or bottom) will be of the same color.

A layer can have only zero, one, or four correct pairs. The number and location of correct pairs can be quickly identified by merely looking at two adjacent side faces (that is, not top or bottom). For a given layer, if you see one correct pair and one incorrect pair, then there is only one correct pair on that layer. If you see two correct pairs, then all four pairs are correct.

If you see no correct pairs but both pairs consist of opposite colors, then there are no correct pairs on that layer. If you see no correct pairs and only one pair consisting of opposite colors, then there is one correct pair on that layer, and it is opposite to the pair with the opposite colors.

Proceed with one of the following sequences depending on how many solved pairs you have. 5 – bottom and top-back pairs solved (average number of turns for this step. 8) Solving Edges At this point, align corners and position centers. The cube is now fully symmetric except for edges. Pick the new top and bottom face depending on what will make solving top and bottom edges easiest. Steps 4 and 5 can be combined, although this requires monitoring more cubies simultaneously and may not yield a speed gain or a reduction in number of movements. See a for details on steps 4 through 6.

Solve Three Top Edges In order to do this step efficiently, you need not position centers and allign corners in the previous step. Instead, you can solve first (or first two opposite) top edge using one or two turns ignoring centers and then, you can solve the top center together with another top edge.

(average number of turns for this step. 9) Solve Three Bottom Edges To reduce the number of turns required, you can combine this and the following step when solving the third bottom edge. There are several possible cases that are easy to find and very efficient.

In addition, you should force yourself to look ahead in this step and try to prevent slower cases to occur. (average number of turns for this step. 12) Solve One More Top or Bottom Edge.

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